All triangles are equilateral


stand 1:28 AM on 3 Jan 2007

Well, I don't know if this is the reason, but it seems that it is possible to construct a triangle where the point M lies outside the triangle.

Ed Davies 6:31 PM on 5 Jan 2007

Can you see what's wrong? Yes, I think so. Should I post it or would that ruin the fun for anybody? I'll just say that I think stand's comment above is in the right direction but not strong enough.

Bolt 3:00 AM on 2 Apr 2014

In case AB is not equal to AC, M lies outside the triangle. If that's the case, |AC|=|RC|-|AR|, and not |AC|=|RC|+|AR|, as stated in the proof.

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